Why are rounds cheaper than bars if they both weigh the same? I just bought 20 - 1oz rounds because they were $1.99 each less than the 1 oz secondary market bar. Ounce for ounce I'd rather stack bars than rounds but I can't pass up that kind of deal.
That is a good question to which I would like to know the answer too as well. In Australia today at a major bullion company they are selling the following one ounce items. 1 oz SILVER coin - 2017 Australian Kangaroo 0.9999 - Perth Mint $26.18 1 oz Silver Bar - 99.99% Minted Silver Kangaroo Bar - Perth Mint $26.27 1 oz silver coin - Sunshine Mint round 99.9% pure $25.68 The American round is cheapest. But in this case the Kangaroo bar is the dearest and more than the legal tender Silver Kangaroo coin. Why would the bar be more expensive than the coin?
I can't see a round being easier to stack than a bar. I would think coins and rounds would be more popular therefore more expensive due to demand with the Numismatic crowd.
Its about the manufacturing and quality of finish. I've worked in minting of rounds and bars and the care that needs to be taken of the dies and minting environment is extreme.
